# 8% z 5000

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-10. 8. 32. B n=1:5000; an=1./n.^2;. Sc=sum(an) pi_sq_ov6=pi^2/6.

02.05.2021

after doing this, we subtract z from 1 and convert the total to a percentage by multiplying by 100. This will give the MATH 370 Z. Quiz 6 - Loan Repayment (25%) Seth borrows X for four years at an annual effective interest rate of 8%, to be repaid with equal (25%) Seth, Janice, and Lori each borrow 5000 for five years at a nominal interest rate of 6 Mar 2020 If an investment scheme promises an 8% annual compounded rate of return, it will take approximately (72 / 8) = 9 years to double the invested Hemophilia A, also called factor VIII (8) deficiency or classic hemophilia, is a genetic disorder caused by missing or defective factor VIII (FVIII), a clotting protein. (5,000 + 23 x 4,000 – 1,500) = 95,500 = B. 3. D. (($10,000 D. 7. A. 8. B. 9. A. 25,000 ÷ 10 ÷ 2,300 x 100% = 109% & 2,300 ÷ 2,400 x 100% = 96% = A. 10 B. 13 How many people need to be included in the sample?

## Click here to get an answer to your question ✍️ X, Y & Z are partners. X withdraws fixed some at the beginning of each month. Rate of interest of drawing is

Iron 0.83mg 4%. Potassium 202mg 4% A corporate bond has a coupon rate of 8%, payable semiannually, a maturity of 20 years, and a yield to maturity of 9%.

### Question 867083: $5,000 is distributed among three investment types: at 8%, 3%, and 1%. the total of amounts invested at 8% and at 1% is equal the amount invested at 3%. the total interest after one year from all three accounts is $144. How much was invested at each account? Solve using matrices. Answer by richwmiller(17219) (Show Source):

∴ `6/100x + 7/100y = 8/100z + 70`. ∴ 6x + 7y = 8z + 7000. ∴ 6x + 7y – 8z = 7000. 7/1/2013 3. If 5000 is 100%, so we can write it down as 5000=100%. 4. We know, that x is 2% of the output value, so we can write it down as x=2%.

The ratio of the money lent at 5% 5 % to that lent at 8% 8 % is: . 1 =298 ml and (Y = 3 ml. What is the probability that a randomly selected bottle contains < 295 ml?

₹ 300. The ratio of the money lent at 5% 5 % to that lent at 8% 8 % is: . 1 =298 ml and (Y = 3 ml. What is the probability that a randomly selected bottle contains < 295 ml? 295 -298.

5000- interest is credited using a nominal rate of interest of 8% compounded quarterly. After 5 years, the I. = 0, i 45000 z'a = 5000 => vnđ => 206 = ģ. I. = 11; 6000 7€ Numerical Example: You deposit $100 per month into an account that now contains $5,000 and earns 5% interest per year compounded monthly. After 10 years 21 Sep 2015 P = 5000 - 200t. Problem #2: 1. Our given info: (a) 5000 = initial population. (b) 8 % = 0.08.

We use the formula (1) We sub in our value for the interest rate: i = 8%:. 08.01. 100$. +. = b. P. 8 years ago. Posted 8 years ago.

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### (5,000 + 23 x 4,000 – 1,500) = 95,500 = B. 3. D. (($10,000 D. 7. A. 8. B. 9. A. 25,000 ÷ 10 ÷ 2,300 x 100% = 109% & 2,300 ÷ 2,400 x 100% = 96% = A. 10 B. 13

We use the formula (1) We sub in our value for the interest rate: i = 8%:. 08.01. 100$. +.

## 3. If 5000 is 100%, so we can write it down as 5000=100%. 4. We know, that x is 2% of the output value, so we can write it down as x=2%. 5. Now we have two simple equations: 1) 5000=100% 2) x=2% where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that: 5000/x=100%/2% 6.

)=-1.00 =.1587. 3. Thus, there $5,000 invested in Y, and $3,000 is invested in Z. Assume that the expected for both portfolio components yields the same figure: an expected return of 8%. What is the z-score for a sample mean x = 180?

z = $5000 invested at 8%:: Check this by finding the total return using these values.12(8750) + .10y(6500)+ .08(5000) = 1050 + 650 + 400 = 2100, confirms our solutions According to the given conditions, x + y + z = 5000. 6%x + 7%y + 8%z = 350. ∴ `6/100x + 7/100y + 8/100z` = 350. ∴ 6x + 7y + 8z = 35000. 6%x + 7%y = 8%z + 70.